Distinct combination selection

I have a need to determine the distinct number of combinations of selections in a fantasy competition - where the competition is to guess the final ladder of a sporting league. Participants order their selection based on who they think will come first, second, third, etc.

It got me thinking... how can I get a distinct count of records grouped by PlayerID with multiple rows? Picture the following:

You can easily see here that PlayerID 100001 and 100173 have the exact same selection. Assuming there are hundreds of entries (which I've omitted on purpose), I want to return a list of selections and how many players have picked that selection.

There are many ways to skin a cat, but making use of STUFF and FOR XML I can generate a concatenated list of selections and then perform a simple count from there. For the purposes of this example, I am going to divide the query up into pieces with #temp tables, though it could easily be returned with one sub-query.

First, collect the players and concatenate their selections making sure to order by position so they're populated in the correct order of selection.

SELECT p1.PlayerID,
      STUFF( (SELECT ','+Team
              FROM ladder p2
              WHERE p2.PlayerID = p1.PlayerID
              ORDER BY Position
              FOR XML PATH(''), TYPE).value('.', 'VARCHAR(MAX)')
           ,1,1,'')
      AS Selection
INTO #selections
FROM ladder p1 
GROUP BY PlayerID

SELECT * FROM #selections

This will return a result set like the following:

Which we can now easily query the counts of distinct selection. Like so:

SELECT Selection, COUNT(Selection) thecount
FROM #selections
GROUP BY Selection
HAVING (COUNT(Selection) >= 1) 
 -- change to >1 if you don't care about unique selection
ORDER BY COUNT(Selection) DESC

Delivering the desired result like the following:

I trust this assists someone and, if time permitted, gets me thinking about other ways to achieve the same outcome.